Which inequality models this problem? miranda started a car-washing business. she spent $75 to purchase supplies to get started and she uses about $0.50 worth of supplies per car washed. miranda charges $9 for each car washed. let c represent the number of cars. what is the minimum number of cars miranda will need to wash to make a profit? 9c> 75+0.5c 0.5c> 75+9c 9c< 75+0.5c 0.5c? 75+9c

Given

Miranda started a car-washing business

She spent $75 to purchase supplies to get started and she uses about $0.50 worth of supplies per car washed.

Miranda charges $9 for each car washed

Find out the minimum number of cars Miranda will need to wash to make a profit.

To proof

As given

let c represent the number of cars.

She spent to purchase supplies to get started = $ 75

she uses worth of supplies per car washed = $ 0.50

Miranda charges  for each car washed = $ 9

than the inequality be

i.e the minimum number of cars  Miranda will need to wash to make a profit is 9 .

Hence proved

tickets for the harlem globetrotters

show at michigan state university in

2010 cost $16, $23, or, for vip seats, $40.

total revenue = 16x + 23y + 40z

if 9 times as many $16 tickets were sold

as vip tickets,

x = 9z => x – 9z = 0, if 9 times as many $16 tickets were sold

as vip tickets,

x = 9z => x – 9z = 0, sales of all three kinds of tickets would

total $46,575.

16x + 23y + 40z = 46575, how many of each kind of ticket would

have been sold?

solve for x, y and z

x − 9z = 0

x − y − z = 55

16x + 23y + 40z = 46575

x = 1170

y = 985

z = 130

welcome!

  the correct choice is marked

step-by-step explanation:

the first two graphs show multiple turning points. the last graphs matches the description in every detail.