Suppose 46% of the students in a university are baseball players. if a sample of 622 students is selected, what is the probability that the sample proportion of baseball players will be greater than 47%? round your answer to four decimal places.

Probability of proportion will greater than 47% = 0.6915

Step-by-step explanation:

Given data:

population proportion p = 0.46

sample proportion b

sample size be n = 622

Probability of proportion will greater than 47%

                          = P(z >0.500)

from standard z table

= 0.6915

step-by-step explanation:

there is a formula i can give you:

it is r^2*n*sin(360/n) divided by 2 where r represents the "radius" and n is the number of sides.

plug them in:

(10sqrt(3))^2*6*sin(360/6) divided by 2

100*3*6*sin(60) divided by 2

900*sin(60)

900*sqrt(3)/2

450*sqrt(3)

approx is 779.4 cm^2