Quadrilateral abcd is located at a(-2, 2), b(-2, 4), c(2,4), and d(2, 2). the quadrilateral is then transformed using the rule (x - 3, y + 4) to form the image a’b’c’d’. what are the new coordinates of a’,b’, c’, d’? describe what characteristics you would find if the cooresponding vertices we’re connected with line segments

Step-by-step explanation:

Given coordinates are-

A(-2,2) , B(-2,4) , C(2,4) , D(2,2)

Now, this coordinates will be changed using the following formula-

x'=x-3 , y'=y+4

That is , we have to subtract  3 from x-coordinate and add 4 with y-coordinate to get the new points.

So,

A'=(-2-3 , 2+4)=(-5 , 6)

B'=(-2-3 , 4+4)=(-5 , 8)

C'=(2-3 , 4+4)=(-1 , 8)

D'=(2-3 , 2+4)=(-1 , 6)

So, the new coordinates are -

A'(-5,6) , B'(-5,8) , C'(-1,8) , D'(-1,6)

And if we connect the coordinates we will get a rectangular prism.

idk but i found this "the graph of y = f(x-2) is the graph of y = f(x) translated two units rightward.  

so, since the point (9,2) lies on the graph of y = f(x), the point (11,2) lies on the graph of y = f(x-2)."

step-by-step explanation:

link is

find out the value of b

step-by-step explanation: