Find the dimensions of a rectangle whose width is 6 miles less than it’s length and whose are is 55 square miles.

area = width * length

or

A = W * L

55 = W * (W+6)

solve for width:

0 = W^2 + 6W - 55

this is a quadratic and has two solutions -11 and 5

a length can only be non-negative so discard -11.

width W = 5 miles

now the length is 5+6 = 11 miles

step-by-step explanation:

the options are kind of confusing. i can tell you what i see going on here when i look at the graph.

the class and exam medians are closely related, and it looks like the low outlier on the exam did pull the median lower. [tex][/tex]

part a

x     y

0     8

1     7.5

2     7

3     6.5

4     6

5     5.5  

for every hour i deducted .5 inches from the length of the candle

part b

it is a function because for every x value there is only one y value

part   c

for every x value there is only one y value

x       y

0       8

1       7.6

2       7.2

3       6.8

step-by-step explanation: