Find a point-slope form for the line that satisfies the stated conditions slope=3, passing through (-3,1)

y=3(x+3)+1

in slope intercept form, it would be 3x+10

the answer is 96 degrees

step-by-step explanation:

you have to realize that a line equals 180 degrees

f(x) = x^3 -2x^2 -3x

x( x^2 -2x-3)

x( x^2 +x -3x -3)

x( x(x+1) -3(x+1))

x( x-3)( x+1)

so zeroes are 0, 3,-1

its (2) option