What are the solutions of 2x^2-6x+5=0

x = ± i

the equation has no real zeros but instead has 2 complex zeros

the discriminant = b² - 4ac

with a = 2, b= - 6, c = 5

b² - 4ac = (-6)² - (4 × 2 × 5 ) = -4

since b² - 4ac < 0  there are no real zeros

using the quadratic formula

x = ( 6 ± √(- 4 ) )/4 = ( 6 ± 2i ) / 4

x = ± i

  = ± i

answer

the correct answer is

explanation

the given function is

the excluded values are obtained by solving:

we factor to obtain:

the excluded values are

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