Arectangular garden is extended 4% on the long sides and 8% on the short sides. to the nearest hundredth of a percent, by what percent does the area of the rectangle increase? (hint: let x = the length of the original long side and y = the length of the original short side. multiple the new side lengths and compare to x*y which is the area of the original rectangle.)

12.32%

Step-by-step explanation:

1. is the original long side and is the original short side.

2. The area of the original rectangle is .

3. The rectangle is extended 4% on the long sides and 8% on the short sides. therefore, the new long side is:

4. And the new short side is:

5. The new area is:

6. The percentage of increase is calculated by substracting the new area and the original area:

7. The result is:

(0.1232)(100)=12.32%

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step-by-step explanation:

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

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