The graph f(x)=x^3-6x^2+4x-3 crosses the x-axis at one point. what is the slope of the graph at that point. round your answer to three decimal place.

We take the derivative of x^3 -6x^2 + 4x -3 which is

3x^2 -12x +4 = 0

Then we have to calculate the equation's value when y = 0 which in this case occurs when x = 5.3579 (the equation's only real root).

3*5.3579 * 5.3579 -12*5.3579 +4 = 25.82647723

which rounds to 25.826

Step-by-step explanation:

domain is all the x values included in the

0 ≤ x ≤ 2

range is all the y values of the graph

-2 ≤ y ≤ 2

***keep in mind that there are different ways to show domain and range

hope this !

~just a girl in love with shawn mendes

c is the correct answer

step-by-step explanation: