Tim plotted the points (2,4) and (6,10). what is the equation of a line that passes through both of tim's points

y = (3/2)x + 1

Step-by-step explanation:

Moving from (2,4) to (6,10), we see that y increases by 6 and x by 4.  Thus, the slope is m = rise / run = 6/4 = 3/2.

Starting with y = mx + b, subst. 3/2 for m, 4 for y and 2 for x, obtaining

b = 4 - (3/2)(2) = 4 - 3 = 1.  Then the desired equation is y = (3/2)x + 1.

since no one answered yet i will give it a shot, not completely sure tho.

i think it should be y=cos(x+2pi), (third answer, answer c)

good luck.

do a bckflip awfwgawgawggw