If the length of the rectangle is three more then two times the width and the perimeter is 56m, what are the dimensions of the rectangle?

Length = 19m

Width = 8m

Step-by-step explanation:

Let the width be x meters

The length will be 2x + 3 meters

The perimeter is 56m

Perimeter is given by 2(length) + 2(width)

2(2x + 3) + 2x = 56m

4x + 6 + 2x = 56m

6x + 6 = 56m

6x = 56 - 6 = 50m

x = 50/6m

Simplifying gives;

x = 8m

Length = 2x + 3 that gives;

2(50/6) + 3 = 50/3 + 3

Working out further gives;

Length = 19m

im not sure

step-by-step explanation:

a 4/6 = 9/12   not proportional

step-by-step explanation:

to find which are not proportional, we can use cross products

if it is true, they are proportional.   if it is not true, they are not proportional.

a 4/6 = 9/12

4* 12 = 6*9

48 = 54

not this is not proportional  

b 2/3 = 12/18  

2* 18 = 3 * 12

36 = 36

this is proportional

c 5/4 = 10/8  

5*8 = 4*10

40 = 40

this is proportional

d 7/5 = 35/25

7*25 = 5 * 35

175 = 175

is proportional