The inside ring of packing tape has a diameter of 80 mm. the tape surrounding the ring is 8 mm beyond the ring. what is the distance around the outer edge of the tape? use 3.14 for π π . 301.44 mm 150.72 mm 48.28 mm 276.32 mm

301.44 mm

Step-by-step explanation:

Diameter of the inside ring of a packing tape = 80 mm

The tape surrounding the ring is 8 mm beyond the ring which means the diameter of the ring including the surrounding will be:

80 + 8 + 8 = 96 mm

and its radius will be = 96/2 = 48.

To find the distance around the outer edge of the tape, we need to calculate the circumference for the ring with the tape on it.

Circumference =

Circumference = 2 x 3.14 x 48 = 301.44 mm

Therefore,  the distance around the outer edge of the tape is 301.44 mm.

here you hope this .

step-by-step explanation:

hypotenuse = √(15² + 8²)

=  √(225 +64)

=  √(289) = 17

sin(x) = cos(y) = 8/17

they are identical so long as you are doing the sine of one angle and the cosine of the only other angle that isn't the right angle.

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