△klm has k> l> m. which angle of the triangle may measure 60°?

Draw the normal from vertex L to side MK and let it meet MK at P.

ΔLMP is 45-45-90 right triangle => LM(hypotenuse)= 12 . So legs MP=LP= 12/√2 = 6√2.

ΔKLP is 60-30-90 right triangle => larger leg= LP=6√2. smaller leg, KP= largerleg / √3 = 2√6.

  LK = hypotenuse 2 x smaller leg = 4√6.

  MK= MP+KP = 6√2 + 2√6

Perimeter = 12 + 4√6 + 6√2 + 2√6 = 12+6√6+6√2 = 6(2+√6+√2) = 35.18

2nd Part:

Draw NP perpendicular to MO, where P is a point on MO.

Using 45-45-90 special right triangle rule on triangle MNP, NP = MN/√2 = 3√2 =MP.

triangle ONP is 30-60-90 triangle. ON = 2 NP = 6√2, OP = NP√3= 3√6.

ON = 6√2 and MO =MP +OP =3√2 +3√6

  the correct choice is marked

step-by-step explanation:

the first two graphs show multiple turning points. the last graphs matches the description in every detail.

the formula for the equation of a circle is (x – h)2+ (y – k)2 = r2, where (h, k) represents the coordinates of the center of the circle, and r represents the radius of the circle. if a circle is tangent to the x-axis at (3,0), this means it touches the x-axis at that point.