Alexis has a rectangular piece of red paper that is 4 cm wide its length is twice its width she glooze a rectangular r alexis has a rectangular piece of red paper that is 4 cm wide its length is twice its width she glued a rectangular piece of blue paper on top of the red piece measuring 3 centimeters by 7 centimeters. how many square centimeters of red paper will be visible on top ?

11 square centimeters of red paper will be visible on top.

Step-by-step explanation:

Width of the rectangular red sheet = w = 4 cm

Length of the rectangular red sheet = l = 2 × 4 cm = 8 cm

Area of the rectangle = l × w

Area of the rectangular red sheet = A

Width of the rectangular blue sheet = w' = 3 cm

Length of the rectangular blue sheet = l' = 7 cm

Area of the rectangular blue sheet = A'

After gluing blue paper on the top of red paper. The area of red paper that will be visible from the top is:

A - A' =

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step-by-step explanation:

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the value of x is 9 ⇒ answer b

step-by-step explanation:

* we can solve this problem using cosine and sine rule

- in δ abc

∵ ab = 36 , bc = 28 , ac = 16

- lets find the measure of angle b using the cosine rule

∵ cos b = [ab² + bc² - ac²]/2(ab)(bc)

∴ cos b = [36² + 28² - 16²]/2(36)(28)

∴ cos b = 19/21

∴ m∠b = cos^-1(19/21) ≅ 25°

- lets find the measure of angle a using the sine rule

∵ sina/bc = sinb/ac = sinc/ab

∴ sina/28 = sin25°/16 ⇒ by using cross multiplication

∴ sina = 28 × sin25°/16

∴ sina = 0.7396

∴ m∠a = sin^-1(0.7396) ≅ 48°

- from the figure m∠abd = m∠dbc

∵ m∠abc = 25°

∴ m∠abd = 25°/2 = 12.5°

- in δabd

∵ m∠a = 48° , m∠abd = 12.5°

∵ the sum of the measures of the interior angles of any δ is 180°

∴ m∠adb = 180° - (48° + 12.5°) = 119.5°

∵ ab = 36

∵ ad = x

- use the sine rule to find x

∵ sin∠adb/ab = sin∠abd/x

∴ sin119.5°/36 = sin12.5°/x ⇒ by using cross multiplication

∴ x = 36 × sin12.5°/sin119.5° = 8.95 ≅ 9

* the value of x is 9