Ln= 6x-5 , lm= x + 7 , and mn= 3x + 20 find mn

This question is based on a principle in Mathematics called the Midpoint of a linelineline

Based on this question, the line = LNLN

To solve this question, we have the expression

LM + MN = LN

Step 1

We solve for x

Given that: LN= 6x-5 , LM= x + 7 , and MN= 3x + 20

Hence,

x + 7 + 3x + 20 = 6x - 5

Collect like terms

7 + 20 + 5 =6x - x - 3x

32 = 2x

Divide both sides by the coefficient of x = 2

32/2 = 2x/2

x = 16

The value of x = 16

Step 2

Find MN

Given that : MN= 3x + 20 and x = 16

We substitute 16 for x in MN

MN = 3(16) + 20

MN = 48 + 20

MN = 68

Therefore, the value of MN is 68.

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68

Step-by-step explanation:

LM   +    MN     =   LN

x + 7  + 3x + 20 = 6x - 5

            4x + 27 = 6x - 5

           -4x         -4x      

                    27 = 2x - 5

                     +5        +5

                    32  = 2x

                    ÷2   ÷2    

                     16 = x

MN: 3x + 20

       3(16) + 20

         48   + 20

               68

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step-by-step explanation:

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