How do you solve for the slope of a line with the equation ax^2 + bx + c?

The graph of y = ax^2 + bx + c A nonlinear function that can be written on the standard form ax2+bx+c,where a≠0 All quadratic functions has a U-shaped graph called a parabola. The parent quadratic function is y=x2 The lowest or the highest point on a parabola is called the vertex. The vertex has the x-coordinate x=−b2a The y-coordinate of the vertex is the maximum or minimum value of the function. a > 0                   parabola opens up                    minimum value a < 0                    parabola opens down              maximum value A rule of thumb reminds us that when we have a positive symbol before x2 we get a happy expression on the graph and a negative symbol renders a sad expression. The vertical line that passes through the vertex and divides the parabola in two is called the axis of symmetry. The axis of symmetry has the equation x=−b2a The y-intercept of the equation is c. When you want to graph a quadratic function you begin by making a table of values for some values of your function and then plot those values in a coordinate plane and draw a smooth curve through the points.

The year before the 10s so it was like when caveman were alive

Using the rise/run rule. you would get 2/6.simp. 1/3