The domain of the function f(x)=3√x is x ≥ 0 but how do i work it out to get that answer?

No real square root of a negative

Step-by-step explanation:

It all comes down the the square root of x. There is no real square root of a negative number  so x must be equal to or greater than 0.

Domain is therefore x >= 0.

The domain in most contexts refers to the independent variable---what you can choose to put in the function.

The answer comes from realizing that square roots real numbers are only defined for non-negative numbers. For example, √(4) = 2 and it represents the number such that multiplying it by itself will get 4, i.e. √(4) · √(4) = 2 · 2 = 4.

But positive times a positive makes a positive product, and negative times a negative also results in a positive product. It is not possible to find a real number such that multiplying it by itself gives you a negative number. The two real numbers being multiplied together must have the same sign because those two numbers are the same number.

This tells us that for 3√(x), we must have that whatever is inside the square root is nonnegative. Hence the domain of the function is x ≥ 0. (Square root of 0 is 0.)

5x+40

5(x + 8)

7x - 49

7(x - 7)

18x + 9

9(2x + 1)

15x - 10

5(3x - 2)

step-by-step explanation:

for number one all you have to do is factor 5 out of 5x + 40

for number 2 factor 7 out of 7x - 49

for number three factor 9 out of 18x + 9

for number four factor 5 out of 15x - 10