Solve the quadratic equation by completing the square. 2x^2 + 2 = 3x express your answer in simplified form. here's my answer, is this correct? 2x^2 + 2 = 3x 2x^2 - 3x + 2 = 0 x^2 - 3/2x + 1 = 0 x^2 – 3/2x = -1 x^2 + 3/2x + 9/16 = -1 + 9/16 (1/2 × -3/2)^2 = 9/16 x^2 + 3/2x + 9/16 = -7/16 (x + ¾)^2 = -7/16 √(x + ¾)^2 = ±√-7/16 x + ¾ = ± i√7/√16 x + ¾ = ± i√7/4 x = -3/4 ± i√7/4 {-3/4 - i√7/4, -3/4 + i√7/4}

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step-by-step explanation:

at least i think its

the value of v.w= -12.

step-by-step explanation:

we are given three vector r,v and w as:

r = < 5, -5, -2> ; v = < 2, -8, -8> ; w = < -2, 6, -5>

we know that r,v and w could also be represented as:

r=5i-5j-2k

v=2i-8j-8k

and w= -2i+6j-5k

where i,j and k are the unit vectors of x,y and z-axis respectively.

also we know that it has the following property:

i.i=1 ; j.j=1; k.k=1

and i.=j.i=i.k=k.i=j.k=k.j=0

i.e. when we multiply two vectors or we find it's dot product we need to only multiply the components of x coordinates with each other; y with each other and z with each other.

hence, v.w= (2i-8j- -2i+6j-5k)

                  = 2×(-2)+(-8)×(6)+(-8)×(-5)

                  = -4-48+40

                  = -12

hence, v.w= -12