Aball is thrown into the air with an initial velocity of 22 meters per second. the quadratic function h(x)= -4.9t square +22t+5.5 represents the height of the ball above the ground, in meters, with respect to time t, in seconds. determine h(3) and explain what it represents

Height of the ball after 3 seconds = 27.4 feet.

Step-by-step explanation:

h(t) = -4.9t^2 + 22t + 5.5

h(3) means the height of the ball at time 3 seconds after the ball was thrown.

h(3) = -4.9(3)^2 + 22(3) + 5.5

=  27.4 feet

The height reached by the ball when the time of motion is 3 seconds is 27.4 m.

The given parameters;

The height reached by the ball when the time of motion, t, is represented as h(3).

The value of this height is calculated as;

h(3) = -4.9(3)² + 22(3) + 5.5

h(3) = -44.1 + 66 + 5.5

h(3) = 27.4 m

Thus, the height reached by the ball when the time of motion is 3 seconds is 27.4 m.

Learn more here:

4.08%

step-by-step explanation:

b. would be the answer : )

step-by-step explanation:

step 1: add -16x to both sides.

16x−4y+−16x=64+−16x  

−4y=−16x+64

step 2: divide both sides by -4.

−4y /-4 = -16x + 64/-4

answer:   y=4x−16

hope i'm right