Amath teacher gave her students two tests. on the first test, 80% of the class passed the test, but only 30% of the class passed both tests. what is the probability that a student passes the second test, given that they passed the first one? 0.256 0.375 0.500 0.625

0.375 is answer

Step-by-step explanation:

Given that the  math teacher gave her students two tests. On the first test, 80% of the class passed the test.  But only 30% of the class passed both tests.

Let A - the students pass I test

B = students pass second test

Then P(A) = 80%=0.8 and P(AB) = 30% =0.30

Required probability =probability that a student passes the second test, given that they passed the first one

= P(B/A) = P(AB)/P(A)

= 0.30/0.80

=3/8

=0.375

Right answer is 0.375

your answer is a

step-by-step explanation:

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step-by-step explanation:

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