What is the area of a rectangle with vertices at (−4, 0) , (−3, 1) , (0, −2) , and (−1, −3) ?

6 square units

Step-by-step explanation:

Graph this rectangle.  Doing so shows that it's located in Quadrants II and III.  The length is the distance between (-3,1) and (0, -2):  √(9+9), or 3√2

The width is the distance between (-4,0) and (-3,1), or √(1+1) = √2.

The area is (length)(width) = 3√2 * √2 = 3(2) = 6 square units.

i would say the third one.

step-by-step explanation: liner would mean in a line and the only one that doesn't look like it's even thinking about forming a line would be the third one

37/3

step-by-step explanation:

step 1: simplify both sides of the equation.

7x+8(x+

1

4

)=3(6x−9)−8

7x+(8)(x)+(8)(

1

4

)=(3)(6x)+(3)(−9)+−8(distribute)

7x+8x+2=18x+−27+−8

(7x+8x)+(2)=(18x)+(−27+−8)(combine like terms)

15x+2=18x+−35

15x+2=18x−35

tep 2: subtract 18x from both sides.

15x+2−18x=18x−35−18x

−3x+2=−35

step 3: subtract 2 from both sides.

−3x+2−2=−35−2

−3x=−37

step 4: divide both sides by -3.

−3x

−3

=

−37

−3

x=

37

3