For which system of equations is (5, 3) the solution? a. 3x – 2y = 9 3x + 2y = 14 b. x – y = –2 4x – 3y = 11 c. –2x – y = –13 x + 2y = –11 d. 2x – y = 7 2x + 7y = 31

D   2x – y = 7    

                   2x + 7y = 31

Solution:

solve for each case and see both the equations have LHS = RHS using the coordinates (5,3)

d. 2x – y = 7

   2x + 7y = 31

2(5)-3= 7  >>>   10-3 = 7   >>> 7 = 7

2(5)+7(3)=31 >>> 10+21 = 31 >>> 31 = 31

For the other options  use (5,3)

a. 3x – 2y = 9                                      

  3x + 2y = 14

15-6 = 9 >> 9=9

15+6 = 14 incorrect

b.  x – y = –2

   4x – 3y = 11

5-3 = -2 >> 2= -2

Incorrect

c. –2x – y = –13

     x + 2y = –11

-10-3 = -13 >>> -13 = -13

5+6 = -11 >>> 11 = -11 incorrect

the answer is d

step-by-step explanation:

y+3=-4(x-2)

y+3=-4x+8

  -3         -3  

y=-4x+5