The sum of three consecutive odd numbers is 87. what is the smallest of these numbers?

27

Step-by-step explanation:

Let the first (the smallest) of these consecutive odd numbers be n.

Then the other two are n+2 and n+4.  Adding up these 3 numbers results in 87 = 3n + 6, so that 3n = 81 and n = 27.

The three consecutive odd integers are 27, 29 and 31.  The smallest is 27.

answear:

a

step-by-step explanation: a

step-by-step explanation: given equation a = h(b 1+b 2)

also we are given values of a, h and b 1 as :

a = 16, h = 4, and b 1 = 3.

in order to solve it for b 2, we need to plug the given values of   a, h and b 1 .

therefore, plugging values of   a, h and b 1   in given equation, we get

16 = 4( 3 + b 2)

first dividing both sides by 4, we get

4 = 3 + b 2

subtracting 3 from both sides, we get

4 -3 = 3 -3 + b 2

1 = b 2.