Aprivate jet had been flying for 2 hours when it encountered strong head winds which reduced its speed by 40 miles per hour. if it took the plane 5 hours to travel 1,380 miles, find its speed before flying into the head winds.

If it took the plane 5 hours to travel 1,380 miles, find its speed before flying into the head winds. Its speed before flying into the head winds is 300 mph

Speed before flying  =x

Distance  = 2x

Total distance = 1380 miles

Distance travelled with head wind = 1380-2x

Speed = x-40

Formulate the equation

2+(1380-2x)/(x-40)= 5

Cross multiply

2(x-40)+1380-2x=5(x-40)

2x-80 +1380-2x=5x-200

Divide both side

5x=1500

x=1500/5

Hence:

x= 300 mph

Inconclusion If it took the plane 5 hours to travel 1,380 miles, find its speed before flying into the head winds. Its speed before flying into the head winds is 300 mph.

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300 mph

Step-by-step explanation:

Let s represent the initial speed of the plane in miles per hour. Then s-40 is the reduced speed after encountering the head wind. The time spent flying against the head wind was 5 - 2 = 3 hours.

... distance = speed×time

... 1380 = s×2 + (s -40)×3

... 1380 = 5s -120 . . . . . . . . . eliminate parenthses

... 1500 = 5s . . . . . . . . . . . . . add 120

... 300 = s . . . . . . . . . . . . . . . divide by 5

im here

step-by-step explanation: