Ayogurt shop allows its customers to add, for no charge, 3 toppings to any yogurt purchased. if the store has 15 possible toppings, how many different 3-topping combinations can a customers choose?

Question says that a yogurt shop allows its customers to add, for no charge, 3 toppings to any yogurt purchased. Also the store has 15 possible toppings.

Now we need to find about how many different 3-topping combinations can a customers choose.

To find that we just need to apply combination formula

which is used to select r items out of n items

we have to find combination of 15 toppings into 3 toppings so we calculate C(15,3) using above formula

Hence final answer is 455.

let's call the solutions x₁ = (5 - 2√7)/3 and x₂ = (5 + 2√7)/3

then the equation is (x-x₁)(x-x₂) = 0

if you fill that in you get a lot of numbers which you can recognize as ax²+bx+c=0.

step-by-step explanation:

you can see that a=1 (there is just an x²)

b = (-5 -2√7 + 2√7 - 5)/3 = -10/3

c = -2√7)/3 ) * (-5+2√7)/3) = -1/3

so your answer is 3x^2 – 10x – 1 = 0