To lose one pound of fat, a 200-pound person must burn 3,500 calories. if that person burns 180 calories by walking for 30 minutes, how many hours and minutes does the person have to walk to lose two pounds? round your answer to the nearest minute.

19.44 hours or 19 hours and 26 minutes.

Step-by-step explanation:

1. To lose 1 pound, a 200-person must burn 3,500 calories. Therefore, to lose 2 pounds that person must burn 7,000 calories.

2. If the person burns 180 calories by walking for 30 minutes or hour, to calculate the time in hours the person has to walk to lose 2 pounds, you can multiply 7,000 calories by   hour and divide by 180 calories:

3. You have:

4. Then, you can express it as following:

19 hours and 26 minutes

third choice down

step-by-step explanation:

the first inequality is based on the number of adults and campers, and the second inequality is based on the cost of feeding both the adult and the camper.

we know that there is room for 525 people max.   it's ok to have less than 525, but it's not ok to have more than 525, so the inequality is less than or equal to.   the number combination of adults (x) and campers (y) cannot exceed this 525 max.   therefore:

x + y ≤ 525

now we talk about cost.   it costs $9 to feed one adult, so depending upon the number of adults you have (x) depends upon how much it will cost to feed that number of adults.   same with the campers, who cost $5 to feed.   the adults can be represented by 9x and the campers can be represented by 5y.   since the budget cannot exceed 1,200, the second inequality is:

9x + 5y ≤ 1200