Afarmer can trade 7 pigs for 3 horses. he can also trade 1 pigs for 5 sheep. how many horses can he get for 8 sheep? (suppose he can get a fractional sheep)

First, let's assign variables:

p = pigs

h = horses

s = sheep

We know that:

7p = 3h

p = 5s

We can input 5s in p:

7(5s) = 3h

35s = 3h

h = 35s/3

h = 11 2/3 s

Multiply both sides by 8:

8h = 88 16/3 s

Simplify the fraction

8h = 93 1/3 s

He can get 8 horses for 93 1/3 sheep

5x+40

5(x + 8)

7x - 49

7(x - 7)

18x + 9

9(2x + 1)

15x - 10

5(3x - 2)

step-by-step explanation:

for number one all you have to do is factor 5 out of 5x + 40

for number 2 factor 7 out of 7x - 49

for number three factor 9 out of 18x + 9

for number four factor 5 out of 15x - 10

what is the answer to this