In a parallel circuit, et = 277 v, r = 56 kω, and xl = 68 kω. what is the phase angle (angle theta)?

Phase angle is 50.527°

Step-by-step explanation:

Given that in a parallel circuit , R=56kΩ and 68kΩ.

And we are asked to find phase angle.

In any circuit, phase angle

Since we don't have any capacitor,

Hence phase angle,

                                                  =50.527°≈50.53°

the figures below are made out of circles, semicircles, quarter … find the area and the perimeter of each figure and give your answers as a completely simplified exact value in terms of π (no approximations). remember that we'll also have to cut whatever areas we get in half, since we're only dealing

step-by-step explanation:

b

step-by-step explanation:

it have 5 sides and 5 identicle angle.the rest does not have the same property as b.

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