Ineed with writing an equation of the line that is perpendicular to the line and passes through (2, 4)?

First find the slope of the original given line:

Slope = 5/3

Points (2,4)

** All perpendicular lines' slope are the negative reciprocal of original slope

- The negative reciprocal of 5/3 is -3/5, therefore -3/5 will be the slope of the       perpendicular line

Equations:

Point-slope form: y=4-3/5(x-2)

Slope-intercept: y=-3/5x+5.2

4= -3/5(2)+b

4= -1.2+b

4+1.2=b

5.2=b

gmt is 4 hrs ahead of edt so just add four hours to 1: 14: 20 (minutes and seconds stay the same)

gmt is 5: 14: 20

hope this !

~just a girl in love with shawn mendes

c

step-by-step explanation:

there is vertical asymptote at x = 2 and x = 0

vertical asymptote occurs at the points where the denominator is 0. so we can say that

x = 2 occurs when there is a factor (x-2) in the denominator, and

x = 0 occurs when there is a factor "x" in the denominator

thus, the denominator of the equation would have "x * (x-2)", this is option c only. that's the correct answer.