Suppose a population of 50 crickets doubles in size every 3 months. how many crickets will there be after 2 years?

This is a Geometric Progression problem.

We can use the formula

= a1 +

= 50 x 2^(8-1)

50 is starting number

2 is doubled

8 is how many sets of 3 months in 2 years

= 50 x 2^(7)

= 50 x 128

= 6400

step-by-step explanation:

the original amount doesn't ''re just looking for the time it takes for 1/2 of the substance to we have

(1/2) =)     take the ln   of both sides

ln (1/2)   = )   and we can write

ln(1/2) = ) lne     and lne   = 1     so we have

ln(1/2) = -.1092t     divide both sides by -.1092

t = ln(1/2)/-.1092 = about 6.347 days = about 6.3 days (rounded)

answer: .64

step-by-step explanation

set up the formula for standard deviation for this set of numbers, then simplify