The point (x, 5/2) lies on the graph of y = x - 1/2. the value of x is 3 2 -3

The value of x is 3

Step-by-step explanation:

Hello

Here we have a linear function

also

we have a coordinate with  unknown independent variable

there is a number x that meets

the value of x is 3

I hope it helps

the rocket cannot penetrate the ground, in a contextual sense, therefore the roots of this equation should be the domain of this function. i'll let you find the roots of this quadratic equation (hint: use the quadratic formula:  

1- c

2-a

step-by-step explanation:

mark brainliest!

given : the shape of his satellite can be modeled by   where x and y are modeled in inches.

now,the given equation   is a equation of parabola.

here, coefficient of x is positive, hence the parabola opens rightwards.

on comparing this equation with standard equation , we get

in standard equation, coordinates of focus=(0,m)

thus for given equation coordinates of focus=(0,1.5)

step-by-step explanation: