How many complex roots does the equation 0=3x5−x4−5x2+1 have? 3 4 5 6

we are given

We can use Descartes rule of sign

This is rule is used to find number positive real roots and negative real roots

Positive real roots:

We will find number of sign changes in this equation

We can it changes from +3 to -1  and -5 to +1

so, number of sign changes =2

so, total number of positive real roots =2

Negative real roots:

We can replace x as -x

now, we can simplify it

now, we will find number of sign changes

we can see that it changes from -5 to +1 only

so, number of sign changes =1

so, number of negative real roots =1

Complex roots:

We are given

degree of polynomial =5

so, total number of roots=5

we know that total root is sum of all roots

Total number of roots = number of positive real roots + number of negative real roots + number of complex roots

now, we can plug values

5=2+1+number of complex roots

so, we get

Number of complex roots =2.........Answer

Here to confirm that the answer is "5", just took the test and got it right so I hope I could help :)

yes

step-by-step explanation:

127

whether it's diameter, or radius, i believe if i remember correctly from school, every amount has to always add up to 180. so if you take 53, and starting adding, long story short, taking 127 and adding it to 53, gives you 180.