What is the sum of ten terms of an infinite geometric series if the first term is 8 and the ratio is 1/2

We use the formula:

S 10 = 8 · [(1/2)^9 - 1] / (1/2 - 1 );

Then, S 10 = 8 · ( 1/512 - 1 ) / ( 1/2 - 1 );

S 10 = 8 · ( - 511 / 512 ) / (-1 / 2 );

S 10 = ( - 511 / 64 ) · ( - 2 );

S 10 = + 511 / 32;

S 10 = 15.96;

Step-by-step explanation:

93.8

step-by-step explanation:

lets say, first number = x

second number = 3x+7

total = 49

(x)+(3x+7)= 49

4x+7 = 49

4x = 42

x = 42/4

x= 10.5

x= 10.5

3x+7 = 3(10.5)+7 = 93.8

hope this

idk

step-by-step explanation: