Input 3 5 4 7 output 6 11 11 21 write an equation, in function notation, that would fit the inputs and outputs in the table. show work that proves your equation is true for the given data.

If we graph the given points then they appear to be in the shape of cubic function so we can use standard formula of cubic function which is

Plug the given points to get four equations

like first point (3,6) so plug x=3 and y=6 into above equation, we get:

or

6=27a+9b+3c+d

Same way by plugging other points form table, we get total four equations as follows:

6=27a+9b+3c+d, 11=125a+25b+5c+d, 11=64a+16b+4c+d, 21=343a+49b+7c+d

Now we just need to solve these equations for a, b, c and d.

Solving them to get values of a, b, c and d, we get:

Now plug them into

So the required equation will be:

Hence required equation in function notation can be written as

Now to prove that above function is correct, we just graph the given points from table and the obtained function.

After graphing the given points from table and the obtained function, We see that points lie on the graph of

Which proves that our equation is correct.

alright well the answers to your question is

2xy/9 hope this have a nice day : )

step-by-step explanation:

answer:

total cost for tiles and paints is $924.  

step-by-step explanation:

we have been given that a community hall is in the shape of a cuboid. the hall is 40m long 15m high and 3m wide.

the paint will be required for 4 walls and ceiling.

let us find area of walls and ceiling.

therefore, the area of walls and ceiling is 1410 square meters.

given: cost for 10 litre of paint is $10 and 10 litre paint covers 25 square meter. therefore,

therefore, the total painting cost is $564.

tiles will be required for floor. let us find the area of floor.

given: 1m squared floor tiles costs $3. so,

therefore, the total tiles cost is $360.

now let us find combined total cost of tiles and paint.

therefore, the combined total cost of tiles and paint is $924.