Two cyclist leaves town 200 mi apart at the same time and travel toward each other. one travels at 10mi/h slower than the other. the they meet in 5 hours, what is the rate of each cyclist

Let x be the rate of speed of slower cyclist

and x+10 = rate of speed of faster cyclist

Distance = Speed * Time

5x + 5(x+10) = 200

5x + 5x + 50 = 200

10x = 200-50

10x = 150

x = 15

Rate of speed of slower cyclist: 15 mph

Rate of speed of faster cyclist = 15+10 => 25 mph

arithmetic sequence

step-by-step explanation:

given that a sequence has terms as

19, 15, 11,

this is represented on a graph

the pattern indicates that the sequence is an arithmetic sequence with i term

a=19 and common difference d =-4

any general term

thus the sequence is reduced by 4 for each successive term starting from 1 and nth term is

24-5n.

first negative term would start after 5th term

5th term =24-25< 0

from 5th term onwards the sequence would be negative.