Arectangle table is two times as long as it is wide. if the area is 50ft^2. find the length and width of the table.

Width = 5

Length = 2*5 = 10

Step-by-step explanation:

Givens

Let the width = W  = x

Let the length = L =  2x

Equation

Area = L * W

Solution

Area = 2W * W                  Substitute into the given equation

Area = 2W^2                     Simplify the right

50    = 2W^2                     Divide by 2

50/2 = 2W^2 / 2                Simplify

25 = W^2                           Switch

W^2 = 25                           Take the square root of both sides

sqrt(w^2) = sqrt(25)

Answers

w = 5 ft

L = 2 * 5 = 10 ft

answer: asdfghjkl,mnbv

step-by-step explanation:

step-by-step explanation:

use pothagarean therom

a^2+b^2=c^2 so first ac

acm is a right triangle because c= 90°

and am (the hypotenuse or c) =16+9 =25

but there is not enough info we need another angle or side length