Arectangle table is two times as long as it is wide. if the area is 50ft^2. find the length and width of the table.

W = 5 ft; L = 10 ft

Step-by-step explanation:

Start by representing the length and width:

W = W

L = 2W

Area of rectangle = L * W = 2W * W = 50 ft^2.  Then 2W^2 = 50 ft^2.

Solving for the width W results in W^2 = 25 ft, or W = 5 ft.

The length, L, is therefore L = 2W = 10 ft.

Check:  Does L * W = 50 ft^2?  Does (5 ft)(10 ft) = 50 ft^2?  YES

(w – 2.5)(w + 2.5)

(–4v – 9)(–4v + 9)

step-by-step explanation: