Determine the possible number of negative zeros when f(x)=x^5 - 3x^3 + 2x^2 + 5x - 4

using Descartes' rule of signs

Count the number of sign changes in f(x)

+ \ - / + / + / -

There are 3 sign changes, hence a maximum of 3 possible positive roots

f( - x) = - + 3x³ + 2x² - 5x - 4

count the number of sign changes in f( - x)

- / + / + / - / -

There are 2 sign changes, hence a maximum of 2 possible negative roots

answer: what are the following choices

dilation scale factor 2: starting with δabc, draw the dilation image of the triangle with a center at the origin and a scale factor of two. notice that every coordinate of the original triangle has been multiplied by the scale factor (x2). dilation with scale factor 2, multiply by 2.