In a parallel circuit, et = 208 v, r = 33 kω, and xl = 82 kω. what is the apparent power?

Apparent power is 1.413Volt-Amps.

Step-by-step explanation:

We are given that in a parallel circuit,,R=33kΩ and =82kΩ.

And we are asked to find apparent power.

Apparent power is the combination of true power and reactive power.

In other words, we can say that in a power triangle apparent power is the hypotenuse where as true power and reactive powers are sides.

Let us find true power , reactive power first and the using Pythagorean theorem we can find apparent power.

True power=

Reactive power=

Hence apparent power=

which expression can be used to convert 80 us dollars (usd) to australian dollars (aud)?

1 usd = 1.0343 aud

1 aud = 0.9668 usd

step-by-step explanation:

sorry just need the points

(0,-3) see attached graph

step-by-step explanation:

a. to solve the system, graph the two equations.

x = y+3 becomes y=x-3 has m=1/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move up 1 unit and 1 unit to the right. plot a point and connect.

y=-4x+3 has m =-4/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move down four units and to the right 1 unit. plot a point and connect.

the solution is the point (x,y) where the two lines intersect. by the graph below it is (0,-3).

b. to solve by substitution, substitute y = -4x-3 into x= y+3

x= (-4x-3) +3

x=-4x

5x=0

x=0

now substitute x = 0 back in to find y.

y= -4(0)-3

y=0-3

y=-3

solution is (0,-3)

c. use elimination by adding the equations together.

x-y=3

4x+y=-3

5x=0

x=0

then substitute into one equation to find y.

y=-4(0)-3

y=-3