In △abc, point p∈ ac with ap: pc=1: 3, point q∈ ab so that aq: qb=3: 4, find the ratios apbq : apbc and aaqp : aabc.

1. If AP : PC = 1 : 3, then AP = x, PC = 3x.

2. If AQ : QB = 3 : 4, then AQ = 3y, QB = 4y.

3. Find the area of triangles AQP and ABC:

Then

4. Note that

From the previous two ratios you have that:

Then

14.3

step-by-step explanation:

add all the numbers together.

9 + 12 + 15 + 16 + 17 + 17 = 86

now, divide 86 by how many numbers we have: 6.

86 / 6 = 14.3

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v