Ned is planning a 248-mile trip from cleveland to cincinnati. he believes he can average 52 miles per hour on the trip. if he needs to be in cincinnati by 1: 00 p. m., what is the latest time he can leave cleveland to make it to cincinnati on time, traviling at this rate?

Hi there!

Here are the important information we know :

The trip is 248 miles

He can drive 52 miles in an hour

Let's start by fiding how long it will take him to drive 248 miles by using the cross product method :

52 miles → 1 hour

248 miles → x hours

(1 × 248) ÷ 52 = x

248 ÷ 52 = x

4.76923077 = x

4.77 ≅ x

0.77 × 60 = 46.2 ≅ 46

So it will take him about 4 hours and 46 minutes to drive 248 miles.

Knowing that he needs to arrive at destination at 1:00PM :

The answer is : he can leave at the latest 4h and 46 minutes before which would be at 8:14AM.

There you go! I really hope this helped, if there's anything just let me know! :)

a 10 percent increase

the answer is a) y= 2 csc [0.5 (x+pi/2)]-1

step-by-step explanation: