Find one value of xxx that is a solution to the equation: (2x+3)^2-4(2x+3)-12=0(2x+3) 2 −4(2x+3)−12=0

x = -5/2 or 3/2

Step-by-step explanation:

If we let z = 2x+3, the equation can be written ...

... z² -4z -12 = 0

and can be factored as

... (z -6)(z +2) = 0

Then the solutions are z = -2, z = 6.

This means the values of x that are solutions are ...

... 2x +3 = {-2, 6} . . . . work with both possibilities at once

... 2x = {-5, 3} . . . . . . . subtract 3

... x = {-5/2, 3/2} . . . . .divide by 2

hope this .

r3t40

answer: i can’t tell you that

step-by-step explanation: