Three consecutive odd integers are such that the sum of the first and second is 31 less than 3 times the third. find the integers (urgent)

Using a system of equations, it is found that the integers are 21, 23 and 25.

A system of equations is when two or more variables are related, and equations are built to find the values of each variable.

In this problem, the three consecutive odd integers are:

n, n + 2 and n + 4.

The sum of the first and second is 31 less than 3 times the third, hence:

n = 21

n + 2 = 23

n + 4 = 25

Hence the integers are 21, 23 and 25.

More can be learned about a system of equations at link

1st:x

2nd x+2

3rd: x+4

(x)+(x+2) = 3(x+4)-31

distribute

2x+2 = 3x+12-31

2x+2 =3x-19

subtract 2x from each side

2 = x-19

add 19 to each side

21 =x

21,23,25

the simplified form is

step-by-step explanation:

we want to simplify the expression,

let us change the middle bar to a normal division sign to obtain,

we multiply the first fraction by the reciprocal of the second fraction to obtain,

we factor to obtain,

we cancel the common factors to get,

we simplify to get,

the correct answer is b

1) 2/5

2) zero=0/1

3) zero=0/2

4) -4/5

5) undefined=3/0