What is the equation, in point-slope form, for a line that goes through (8, −4) and has a slope of −56 ? y−4=−56(x+8) y+4=−56(x−8) y+4=−56(x+8) y−4=−56(x−8)

The point-slope form:

We have the point (8, -4) and the slope m = -56. Substitute:

answer: (c) m∠qpo + (2x + 16)° = 180°

step-by-step explanation:

the opposite angles of a quadrilateral are supplementary.

so, ∠o + ∠q = 180°   and   ∠p + ∠r = 180°

since ∠r = 2x + 16°, we can use substitution as follows:

∠p + ∠r = 180°

∠p + (2x + 16)° = 180°