What is x^2-12x+23=7 in vertex form?

y = (x - 6)^2 - 20

Step-by-step explanation:

Let's start by completing the square for x^2 - 12x.  Half of the coefficient of x is (1/2)(-12), or -6.  Square this and add it to x^2 - 12x, and then subtract it:

x^2 - 12x + 36 - 36 + 23 = 7

Rewriting the first three terms,

(x - 6)^2 -13 = 7, or

y = (x - 6)^2 - 20

The vertex is located at (h,k), which here is (6, -20).

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step-by-step explanation: