Use the identity x3+y3+z3−3xyz=(x+y+z)(x2+y2+z2−xy−y z−zx) to determine the value of the sum of three integers given: the sum of their squares is 110, the sum of their cubes is 684, the product of the three integers is 210, and the sum of any two products (xy+yz+zx) is 107. enter your answer as an integer, like this: 42

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the sum of their squares is 110, So

the sum of their cubes is 684, so  

the product of the three integers is 210, so xyz= 210

the sum of any two products (xy+yz+zx) is 107

Now we plug in all the values in the identity

684 - 3(210) = (x+y+z)(110-107)

684 - 630 = (x+y+z)(3)

54 = 3(x+y+z)

Divide by 3 on both sides

18 = x+y+z

the value of the sum of three integers is 18

true

step-by-step explanation:

$2416.6

step-by-step explanation:

per hour = $ 25

total work time = 35

commission = 15%

total she has to make = $ 4,500

let she sold x dollar products

so her commission will be 15 % of x

now

total = weekly basic pay + commission

4500= (25*35) + 15 % of x

4500=875 + * x

4500-875 =   * x

3625= * x

multiplying wwith 100 on both sides gives

36250 = 15 x

now

x =  

x= $2416.6