Abag contains 4 white, 3 black, and 6 green balls. balls are picked at random. explain why the events picking a white ball and then another white ball without replacement are dependent. then, identify the probability. a. p(white) is different when it is known that a white ball has been picked already. p(white and white) = 4/11 b. p(white) is the same when it is known that a white ball has been picked already. p(white and white) = 1/12 c. p(white) is the same when it is known that a white ball has been picked already. p(white and white) = 1/9 d. p(white) is different when it is known that a white ball has been picked already. p(white and white) = 1/13

D

Step-by-step explanation:

D is the correct answer because first of all, there are 13 balls total. So the denominator would have to be 13. Also, white is the second largest number of balls in the set, so it is pretty likely that you will pick it. Although the most common picked would be green since it has the most balls.

example 2 – simplify: step 1: completely factor both the numerators and denominators of all fractions. step 2: change the division sign to a multiplication sign and flip (or reciprocate) the fraction after the division sign; essential you need to multiply by the reciprocal. step 3 : cancel or reduce the fractions.

answer: it's d

step-by-step explanation: