Do question 3 that picture goes with it

We are given two chords of a circle intersecting at C point.

According to intersection rule of chords of a circle

AC × CV = WC × CU

Plugging values of TC, CV, WC and UC in formula, we get

14(2x+2) = 12 (2x+5)

28x + 28 = 24x + 60.

Subtracting 28 from both sides, we get

28x + 28-28 = 24x + 60-28.

28x = 24x + 32.

Subtracting 24x from both sides, we get

28x-24x = 24x-24x + 32.

4x = 32.

Dividing both sides by 4, we get

x = 8.

We need to find the length of TV.

TV = 14+ 2x+2.

Plugging x=8, we get

TV = 14 + 2(8) +2 = 14 +16 +2 =32.

i do not know the answer

step-by-step explanation:

you didn't post any answer choices, so its not 100% clear what your teacher is looking for

however, log(15/7) is equivalent to log(15) - log(7)

i'm using the rule log(x/y) = log(x) - log(y)