Abasketball tournament starts with 128 teams. in each round half of the teams are eliminated how many teams remain after 5 rounds

Total number of team in starting = 128 teams.

In each round half of the teams are eliminated.

Therefore, number of teams remain after first round = 128/2 = 64.

The number of teams remain after second round = 64/2 = 32.

The number of teams remain after third round = 32/2 = 16.

The number of teams remain after fourth round = 16/2 = 8.

The number of teams remain after fifth round = 8/2 = 4.

After five rounds, only 4 teams remain.

Step-by-step explanation:

at the begginning we have 128 teams, after the first round, we have half of that, this is 128/2.

after the second round, we have half of that: (128/2)/2 = 128/(2*2)

and so on, so if n is the number of rounds, the amount of theams left can be written as:

t(n) = 128/(2^n)

and for n= 5, we have:

t(5) = 128/(2^5) = 128/32 = 4

After five rounds, only 4 teams remain.

this shows a reflection over the x-axis and is translated one unit down and 6 units to the right (x + 6, y - 1)

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step-by-step explanation:

if you want to solve percent error follow these steps.

1. subtract the accepted value from the experimental value.

2. take the absolute value of step 1.

3. divide that answer by the accepted value.

4. multiply that answer by 100 and add the % symbol to express the answer as a percentage.

if you want to solve percent of change just do this.

1. work out the difference (increase) between the two numbers you are comparing.

2. divide the increase by the original number and multiply the answer by 100. if your answer is a negative number then this is a percentage decrease.

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