Identify the vertex, the axis of symmetry, the maximum or minimum value, and the range of the parabola. yequalsxsquaredplus2xplus1 the vertex is nothing. (type an ordered pair.)

Vertex = (-1, 0)

The axis of symmetry is x = -1

Minimum point is (-1, 0)

Range is y ≥ 0

In the interval notation [0, ∞)

Step-by-step explanation:

The given function is y = x^2 +2x + 1.

Write the given equation in the form of y = (x -h)^2 + k.

Here (h,k) is the vertex.

y = x^2 + 2x + 1

y = (x + 1)^2

Vertex = (-1, 0)

Axis of symmetry

The axis of symmetry splits the parabola in 2 equal parts.

In this equation, the axis of symmetry is x = -1

Maximum/minimum value

The parabola goes maximum when there is negative sign, it goes minimum when there is positive sign.

Here we have positive sign in front of (x + 1)^2, therefore, it is minimum at

y= 0

When y =0, x = -1

Therefore, minimum point is (-1, 0)

Range

Y- axis represents the range.

Here the minimum is 0, the maximum goes upto infinity.

Range is y ≥ 0

In the interval notation [0, ∞)

Herewith I have attached the graph of the function.

the diameter is 16 cm. are you a teacher?

step-by-step explanation: