If the equation below is solved by graphing, which statement is true? log(6x+10)=log1/2x the curves intersect at approximately x = 0.46. the curves intersect at approximately x = 0.75. the curves intersect at approximately x = 1.11. the curves intersect at approximately x = 3.07.

.46

Step-by-step explanation:

If you graph the function, you can see where the two logs intersects. View the image I have attached.

If the equation log(6x+10)=log(1/2) x is solved by graphing, the curves intersect at approximately x=0.46

Step-by-step explanation:

Equation

log(6x+10)=log(1/2) x

We must graph two functions:

f(x)=log(6x+10) and

g(x)=log(1/2) x→g(x)=log0.5 x

If we graph these two equation the point of intersection is approximately (0.464, 1.107)=(x,y)

x=0.464→x=0.46

y=1.107→y=1.11

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?